Since it's a named result (though not one I've found much use for), I'll start by stating it in it's usual form:
If X is a random variable from a distribution with mean μ and variance σ2, then P(|X ‑ μ| ≥ kσ) ≤ k‑2.
OK, great. Now consider a random sample from the same distribution: X1, ..., Xn. Suppose we don't know what μ and σ2 are. What can we say about the bound using just the sample mean and standard deviation? Well, get ready...
So far, just another messy formula but, it gets better. What's g?
Ummm, OK, you have a function of t and the answer in terms of ν and a. Oh, yeah, don't stress about that; they're both functions of t:
Oh, that's right, they're also a functions of n WHICH ISN'T ANYWHERE TO BE FOUND IN THE PARAMETER LIST. That's nuts. I'm not going to spend a lot of time trying to come up with a better way to express a result that I don't care about, but there simply has to be something better than that.
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