Tuesday, October 25, 2016

Conditional expectations and variances

Well, that's all well and good to have a theorem relevant to my research, but we need to get back to Q topics. I promised myself I'd get through Probability Theory by the end of the month.

If X and Y are random variables then:
  • E(X) = E(E(X|Y)), provided the expectations exists.
  • Var(X) = E(Var(X|Y)) + Var(E(X|Y)), provided the expectations exist.
The proofs for both of these are largely symbol manipulation exercises, but the results are worth knowing. Both results are necessary to prove the blocksum theorem I stated yesterday.

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